I am using the following for loop code to print a star pattern and the code is working perfectly fine.
Here is my code:
for i in range(1,6):
for j in range(i):
print("*", end=" ")
print()
This code displays:
*
* *
* * *
* * * *
* * * * *
Now, my question is how to print the output like this:
*
* *
* * *
* * * *
* * * * *
Actually, that can be done in a single loop:
for i in range(1, 6):
print (' ' * (5 - i), '* ' * i)
You just need to add spaces before the *:
for i in range(1,6):
for j in range(6-i):
print(" ", end="")
for j in range(i):
print("*", end=" ")
print()
Here's the easiest way to print this pattern:
n = int(input("Enter the number of rows: "))
for i in range(1,n+1):
print(" "*(n-i) + "* "*i)
You have to print spaces (n-i) times, where n is the number of rows and i is for the loop variable, and add it to the stars i times.
This can be achieved in one loop and center padding.
n = int(input('Enter the row you want to print:- '))
sym = input('Enter the symbol you want to print:- ')
for i in range(n):
print((sym * ((2 * i) + 1)).center((2 * n) - 1, ' '))
# right angle triangle
for i in range(1, 10):
print("* " * i)
# equilateral triangle
# using reverse of range
for i , j in zip(range(1, 10), reversed(range(1, 10)):
print(" " * j + "* " * i)
# using only range()
for i, j in zip(range(1, 10), range(10, -1, -1):
print(" " * j + "* " * i)
Method #1: Comprehension version
This could be easiest way to print any pattern in Python
n = 5
print('\n'.join([('* '*i).center(2*n) for i in range(1,n+1)]))
Use center method of str, give it a width as parameter and it will centered the whole string accordingly.
Method #2: Regular version
n = 5
for i in range(1,n+1):
print(('* '*i).center(2*n))
#n=Number of rows
def get_triangle(n):
space,star=" ","* "
for i in range(1,n+1):
print((n-i)*space + star*i)
get_triangle(5)
Where n is the number of rows and I is a variable for the loop, you must print spaces (n-i) times and then add it with stars I times. You'll get the desired pattern as a result. For better comprehension, go to the code stated above.
Try this:
def triangle(n):
k = 2*n - 2
for i in range(0, n):
for j in range(0, k):
print(end=" ")
k = k - 1
for j in range(0, i+1):
print("* ", end="")
print("\r")
n = 5
triangle(n)
Description:
The 1st line defines the function demonstrating how to print the pattern
The 2nd line is for the number of spaces
The 3rd line is for the outer loop to handle number of rows
Inside the outer loop, the 1st inner loop handles the number of spaces and the values change according to requirements
After each iteration of the outer loop, k is decremented
After decrementing the k value, the 2nd inner loop handles the number of columns and the values change according to the outer loop
Print '*' based on j
End the line after each row
This can be done in a single loop like the code below:
j=1
for i in range(10,0,-1):
print(" "*i,"*"*j)
j+=2
Here is another way
size = 7
m = (2 * size) - 2
for i in range(0, size):
for j in range(0, m):
print(end=" ")
m = m - 1 # decrementing m after each loop
for j in range(0, i + 1):
# printing full Triangle pyramid using stars
print("* ", end=' ')
print(" ")
def triangle(val: str, n: int, type: str):
for i in range(n):
if type == "regular":
print((i + 1) * val)
elif type == "reversed":
print((n - i) * val)
elif type == "inverted":
print((n - (i + 1)) * " " + (i + 1) * val)
elif type == "inverted reversed":
print(i * " " + (val * (n - i)))
elif type == "triangle":
print((n - (i + 1)) * " " + ((2*i)+1) * val)
Call the function like this
triangle("*", 5, 'triangle')
Output
*
***
*****
*******
*********
#prints pyramid for given lines
l = int(input('Enter no of lines'))
for i in range(1,l +1):
print(' ' * (l-i), ('*') * (i*2-1))
.very simple answer.. don't go for complex codes..
first try to draw a pyramid. by * ..then u easly understand the code..my solution is.. simplest..here example of 5 lines pyramid..
number_space = 5
for i in range (5)
print('/r')
print (number_space *" ", end='')
number_space=number_space-1
for star in range (i+1):
print("*",end=" ")
Use String Multiplication, To simply multiply a string, this is the most straightforward way to go about doing it:
num = 5 for e in range(num, 0, -1): print(" "(e-1)+(""(num-e+1))+(""*(num-e)))
j=1
for i in range(5,0,-1):
print(" "*i, end="")
while j<6:
print("* "*j)
j=j+1
break
function printPyramid($n)
{
//example 1
for ($x = 1; $x <= $n; $x++) {
for ($y = 1; $y <= $x; $y++) {
echo 'x';
}
echo "\n";
}
// example 2
for ($x = 1; $x <= $n; $x++) {
for ($y = $n; $y >= $x; $y--) {
echo 'x';
}
echo "\n";
}
// example 3
for($x = 0; $x < $n; $x++) {
for($y = 0; $y < $n - $x; $y++) {
echo ' ';
}
for($z = 0; $z < $x * 2 +1; $z++) {
echo 'x';
}
echo "\n";
}
}
#CPP Program for Print the dynamic pyramid pattern by using one loop in one line.
https://www.linkedin.com/posts/akashdarji8320_cpp-cplusplus-c-activity-6683972516999950336-ttlP
#include
using namespace std;
int main() {
int rows;
cout<<"Enter number of rows :: ";
cin>>rows;
for( int i = 1, j = rows, k = rows; i <= rows*rows; i++ )
if( i >= j && cout<<"*" && i % k == 0 && (j += rows-1) && cout<<endl || cout<<" " );
}
