PHP in_array with regexp haystack array

Question

Does the PHP function in_array accept a REGEXP array as second argument ? I couldn't find any relevant information on PHP.net

This is the code I'm currently using :

$haystack = [
    "/^foo$/",
    "/^bar$/",
    "/^foobar$/"
];

function in_reg_array($needle, $haystack) {
    foreach ($haystack as $straw)
        if (preg_match($straw, $needle))
            return TRUE;
    return FALSE;
}

If anyone has a better solution, I'm open to suggestions.

Edit :

I can't use a single regexp with foo|bar|foobar because the haystack varies.

I know this, but this is a sample, the one I use has variable amount of regexes. — Jean-Marc Zimmer
– Jean-Marc Zimmer, Commented Dec 6, 2018 at 16:19
In @FelippeDuarte suggestion, remember that $haystack should not contain /^ and $/, so $haystack = ['foo', 'bar', 'foobar'] — Marco Pallante
– Marco Pallante, Commented Dec 6, 2018 at 16:28

Alex Howansky · Accepted Answer · 2018-12-06 16:28:46Z

1

preg_filter() takes an array of patterns, replaces them, and returns the replaced string. So, if it returns nothing, then you know there were no matches.

function in_reg_array($needle, $haystack) {
    return preg_filter($haystack, '', $needle) !== null;
}

edited Dec 6, 2018 at 16:28

answered Dec 6, 2018 at 16:25

Alex Howansky

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Jean-Marc Zimmer Over a year ago

Why didn't I think of preg_filter earlier ? ^^

Felippe Duarte · Accepted Answer · 2018-12-06 16:30:31Z

1

Another option:

$haystack = [
    "^foo$",
    "^bar$",
    "^foobar$"
];

$string = ['foo', 'bar','baz', 'foo2'];

$result = preg_grep("/(".implode('|',$haystack).")/", $string);

Output:

array(2) {
  [0]=> string(3) "foo"
  [1]=> string(3) "bar"
}

answered Dec 6, 2018 at 16:30

Felippe Duarte

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