Replace regex-matched word with modified version of the word

Question

I am trying to replace a 10-digit number I find with regex, with the same word pre-pended with "abc". For example, if the matched number is 0123456789, I want to replace that word with abc0123456789 instead.

Googling around, I found that sed is useful for replacing words in a file -

sed -i '' -e 's/[0-9]\{10\}/new-word/g' *.csv

This command successfully replaced my 10-digit number instances with "new_word". How do I instead replace it with "abc + [matched word]" ?

choroba · Accepted Answer · 2018-12-10 23:16:31Z

-1

Use parentheses to create a "matching capture group". To refer to the first group, use \1, and so on:

s/\([0-9]\{10\}\)/abc\1/g

Or use & which stands for "the whole matching part":

s/[0-9]\{10\}/abc&/g

answered Dec 10, 2018 at 23:16

choroba

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