How can i select particular items of array with Bash

Question

I have an array which i want to create a new array based on that, which contains just my particular selected items by index number.

for example i want to have an array which contains just two and five or with index number [2,4]

do you have an idea how to do it with bash script. i am new in bash thanks

array1=( one two three four five )
echo ${array1[@]}

result

array2 = (two five)

Tom Fenech · Accepted Answer · 2018-12-12 13:32:29Z

2

As far as I'm aware, the only way that you can do this is by making a new array, picking each element one by one:

array2=( "${array1[1]}" "${array1[4}}" ) # two five

If on the other hand you wanted a slice (consecutive indices), you could use the built-in syntax:

array2=( "${array1[@]:1:3}" ) # two three four

answered Dec 12, 2018 at 13:32

Tom Fenech

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Comments

chepner · Accepted Answer · 2018-12-12 14:17:05Z

0

You would need a loop:

indices=(1 3)
for i in "${indices[@]}"; do  # or for i in 1 3, if you want to hard-code the indices
  array2+=("${array[i]}")
done

answered Dec 12, 2018 at 14:17

chepner

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