Get the number of required and non required Arguments in Functions

Question

I want to get the Number of required Arguments and non. I would be really happy if someone could help me, I am kinda stuck here.

I have tried following, I don't know if that is the right way to go for it.

from inspect import signature

def Test(X, Y = 4):
print(X,Y)

R = str(signature(Test))
cu = ""
for i in R:
    if i.isalpha():
        cu = "".join([cu,i])
print(len(cu))
#Output: 2 (I would like to have something like req_Arg = 1, non_req_Arg = 1)

I am using py 3.0

Thank you for suggestions in advance.

What do required arguments and non required arguments mean? How do you want to calculate them? — Mohit Motwani
– Mohit Motwani, Commented Feb 5, 2019 at 6:04
I mean with required Argument in a Function for Example ( def(X, Y = 4: ...), where X is required to run the function. Y wouldn't be, because it has a standard Variable — Paul
– Paul, Commented Feb 5, 2019 at 6:16

Demian Brecht · Accepted Answer · 2019-02-05 06:07:49Z

1

You can get the type of parameter and whether or not it has a default by iterating through inspect.signature(Test).parameters.values():

>>> for param in inspect.signature(Test).parameters.values():
...     print(param.kind, param.default)
...
POSITIONAL_OR_KEYWORD <class 'inspect._empty'>
POSITIONAL_OR_KEYWORD 4

(https://docs.python.org/3.4/library/inspect.html#inspect.Parameter)

It'd be relatively trivial to translate that into the output you're looking for (leaving the exercise up to you).

answered Feb 5, 2019 at 6:07

Demian Brecht

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