Add year/month/day to an UNIX timestamp with just hour/min/sec in python

Question

The range of my timestamp is from 34200 to 57600, so it covers a part of one day from 9:30 AM). I want to add a specific year/month/day to this timestamp. How can I do that in python? Suppose that my timestamp is 34201.054427731004. I want a timestamp with information about year/month/day (for example, 3/2/2017) as the output. So here, the UNIX output is a full timestamp not just the hour/mean/sec.

Unclear how either 34200 or 57600 "cover a 24h day", or what the expected result is. — deceze
– deceze ♦, Commented Feb 25, 2019 at 13:51
It does not cover 24h : 34200 is 9hours and 30 minutes and 57600 is 16 hours — gogaz
– gogaz, Commented Feb 25, 2019 at 13:52
Yeah, still not much better. Instead of describing what you think you have or want, show us what concrete values you expect to get here. — deceze
– deceze ♦, Commented Feb 25, 2019 at 13:55
Yeah, not seeing how 34201.054427731004 relates to "3/2/2017" at all. — deceze
– deceze ♦, Commented Feb 25, 2019 at 13:56

deceze · Accepted Answer · 2019-02-25 14:05:15Z

2

Make a datetime object with the date, which will initialise hours and minutes to 0, and add a timedelta with the seconds to it:

from datetime import datetime, timedelta

date = datetime(2017, 2, 3) + timedelta(seconds=34201)
print(date.timestamp())

answered Feb 25, 2019 at 14:05

deceze♦

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2 Comments

Eghbal Over a year ago

Is this consider .054427731004 part of timestamp?

deceze Over a year ago

If you add them (seconds=123.456), yes.

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