merge two dictionaries with same key values

Question

I have two dictionaries which consist same keys

a = {'a':[3,2,5],
     'b':[9,8],
     'c':[1,6]}

b = {'b':[7,4],
     'c':[10,11]}

When i merge them the keys of dictionary b replaces the keys of a because of the same name. Here's the merge code I am using

z = dict(list(a.items()) + list(b.items()))

Is there somehow I can keep all the keys, I know dictionaries can't have same key name but I can work with something like this:

a = {'a':[3,2,5],
     'b':[9,8],
     'c':[1,6],
     'b_1':[7,4],
     'c_1':[10,11]}

@Jens Seems a bit too generic to name a package...not a very helpful comment... — Rohit Kumar
– Rohit Kumar, Commented Mar 13, 2019 at 7:21

Mykola Zotko · Accepted Answer · 2019-03-13 08:03:51Z

2

You can use a generator expression inside the method update():

a.update((k + '_1' if k in a else k, v) for k, v in b.items())
# {'a': [3, 2, 5], 'b': [9, 8], 'c': [1, 6], 'b_1': [7, 4], 'c_1': [10, 11]}

edited Mar 13, 2019 at 8:03

answered Mar 13, 2019 at 7:39

Mykola Zotko

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1 Comment

DirtyBit Over a year ago

Finally something pythonic!

Niladri Basu · Accepted Answer · 2019-03-13 07:27:31Z

1

Do something like this perhaps:

a = {'a':[3,2,5],
     'b':[9,8],
     'c':[1,6]}

b = {'b':[7,4],
     'c':[10,11]}

z = {}

for key in a:
    if key in b:
        z[key + "_1"] = b[key]
        z[key] = a[key]
    else:
        z[key] = a[key]


print(z)

Output:

{'a': [3, 2, 5], 'b_1': [7, 4], 'b': [9, 8], 'c_1': [10, 11], 'c': [1, 6]}

answered Mar 13, 2019 at 7:27

Niladri Basu

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Comments

Kristopher Ives · Accepted Answer · 2019-03-13 23:21:43Z

1

While I think Usman's answer is probably the "right" solution, technically you asked for this:

for key, value in b.items():
  if key in a:
    a[key + "_1"] = value
  else:
    a[key] = value

edited Mar 13, 2019 at 23:21

answered Mar 13, 2019 at 7:23

Kristopher Ives

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3 Comments

DirtyBit Over a year ago

for key, value in b: ValueError: not enough values to unpack (expected 2, got 1)

Pradeep Pandey Over a year ago

if case is not merging the value of list a and b for matching key and code is giving error: ValueError: not enough values to unpack (expected 2, got 1)

Kristopher Ives Over a year ago

@PradeepPandey This is technically what OP asked for and given their examples.

Pradeep Pandey · Accepted Answer · 2019-03-13 08:25:13Z

0

Check if key of b present in a then add in a with key_1 value of b for key other wise add in key in a the value of b for key.

a = {'a':[3,2,5],
     'b':[9,8],
     'c':[1,6]}

b = {'b':[7,4],
     'c':[10,11]}
for k in b:
    if k in a:
        a[k+'_1']=b[k]
    else:
        a[k]=b[k]
print(a)

edited Mar 13, 2019 at 8:25

answered Mar 13, 2019 at 8:13

Pradeep Pandey

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1 Comment

DirtyBit Over a year ago

Again, not the output OP wants.

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