3

I am trying to create a nested list. The result would be something like [[0,1],[2,3],[0,4]] I tried the following and got an index out of range error:

list = []
list[0].append(0)

Is it not appending 0 to the first item in the list? How should I do this? Many thanks for your help.

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  • 2
    "Is it not appending 0 to the first item in the list?" What first item in the list? That list is empty. Commented Apr 3, 2019 at 9:51
  • 1
    I must notice that shadowing built-in name list with list = [] is not a good idea. Commented Apr 3, 2019 at 11:18

3 Answers 3

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3

A little typo, you should do:

list = [[]]
list[0].append(0)

You need to have a first element first...

Edit:

Use:

list = []
for i in range(3):
    list.append([])
    list[-1].append(0)
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2 Comments

Thanks. But if it is in a loop, how do I initialise the n item before append?
@user4046073 Edited mine,
1

For that you'll need to append a list to a list first, i.e.:

list = []
list.append([])
list[0].append(0)
print(list)
# [[0]]
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0 
lst = []
lst.append([0,1])
lst.append([2,3])
lst.append([0,4])
print(lst)

How about this ? Or you need in the form of loop with constant set of numbers?

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