How do you use regex to parse text across multiple lines from a log file?

Question

I have a log output, summarized below. I need to parse the Final Input, which goes across multiple lines. I cannot find a regex expression that works.

04/10/2019 02:52:59 PM INFO: Model Details:
04/10/2019 02:53:12 PM INFO: Final Input: [  220.12134       3.7499998    75.00001     111.44428      22.500004
    37.5          73.361534  1000.709    ]
04/10/2019 02:53:12 PM INFO: Difference: [ 11.974823 647.91406 ]
04/10/2019 02:53:12 PM INFO: Number: 169
04/10/2019 02:53:12 PM INFO: Time: 13.554227686000004 seconds

I'd like a numpy array output:

[220.12134, 3.7499998, 75.00001, 111.44428, 22.50000437.5, 73.361534, 1000.709]

Using the following code, I can get this to work for single lines:

log_file_path = some_log.log
#regex = '\[(.*?)\]'
regex2 = '(Final Input: \[)(.*?)(\]|\n)'

with open(log_file_path, 'r') as file:
    all_log_file = file.read()
    a = re.findall(regex2, all_log_file)
    print(a)

file.close()
#x = list(map(float, a.split()))

I get the following output, which is missing the Final Input values on the next line (I can parse the output below into a numpy array):

[('Final Input: [', '  220.12134       3.7499998    75.00001     111.44428      22.500004', '\n')]

gmds · Accepted Answer · 2019-04-11 23:24:53Z

1

Use a non-greedy specifier, along with re.DOTALL, which signifies that . includes \n:

import re

regex2 = '(Final Input: \[.+?\])'

a = re.findall(regex2, text, re.DOTALL)
a

Output:

['Final Input: [  220.12134       3.7499998    75.00001     111.44428      22.500004\n    37.5          73.361534  1000.709    ]']

answered Apr 11, 2019 at 23:24

gmds

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