How to print objects except one, without deleting anything (JavaScript) [duplicate]

Question

So i want to filter object of objects, and print all of them except one, which i specify by key.

const obj = {1: {age: 10}, 2: {age: 20}};

console.log(obj);

So i must have option to somehow specify that i don't want the obj[1] to be printed. How do i do that? : |

adiga · Accepted Answer · 2019-04-16 13:30:31Z

5

You could destructure the object:

const obj = {1: {age: 10}, 2: {age: 20}, 3: {age: 30}},
      key = 1;
      
const { [key]:_, ...rest } = obj
console.log(rest);

answered Apr 16, 2019 at 13:30

adiga

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Comments

Maheer Ali · Accepted Answer · 2019-04-16 13:30:00Z

4

You can filter() the keys and then convert it back to object using reduce()

const obj = {1: {age: 10}, 2: {age: 20}};

let key = 1
console.log(Object.keys(obj).filter(x => x != key).reduce((ac,a) => ({...ac,[a]:obj[a]}),{}));

Using the new feature Object.fromEntries

const obj = {1: {age: 10}, 2: {age: 20}};

let key = 1
let res = Object.fromEntries(Object.entries(obj).filter(x => x[0] != key));
console.log(res);

answered Apr 16, 2019 at 13:30

Maheer Ali

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