int (*rdPtrList[4])(unsigned int addr, unsigned int data);
The above declares an array of size 4 of pointers for functions that returns an int and takes two unsigned int. I would like to make a pointer to this array. Is this possible in C?
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3 Answers
Leaving out the parameters to keep the following easier to read:
p -- p
*p -- is a pointer
(*p)[4] -- to a 4-element array
*(*p)[4] -- of pointers
(*(*p)[4])() -- to functions
int (*(*p)[4])(); -- returning int.
Comments
Ah, tricky tricky!!!
I think this works
int (*(*rdPtrList)[4])(unsigned int addr, unsigned int data);
because the compiler tells me _countof(*rdPtrList) is 4.
(I wish you could just say int function(unsigned int addr, unsigned int data)[4]* like you can in D, it's so much more readable: it would be a "function array pointer".)
3 Comments
jliu83
This compiled, I will have to get back to you as to whether it worked!
user541686
@jliu83: Haha okay! (It probably did. :P)
Theodore Murdock
The right way to verify that you declared the pointer correctly is to assign the address of the array to it, i.e.
ptr_to_fixed_length_function_array = &array_of_functions;. If the type isn't correct, your compiler should complain about this assignment.Try this:
typedef int(*rdPtrList_t[4])(unsigned int addr, unsigned int data);
rdPtrList_t *ptrToArray;
