unique_ptr usage in c++ [duplicate]

Question

How do I pass the unique_ptr in the below code? This code does not compile.

int abc(int*& a)
{  
    return 1;
}

int main()
{
    std::cout<<"Hello World";
    std::unique_ptr<int> a(new int); 
    abc(a.get());
    return 0;
}

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– Some programmer dude, Commented Apr 25, 2019 at 7:19
unique_ptr::get returns raw pointer by value, you cannot bind Rvalue (temporary object) - a.get() to non-const Lvalue reference. Change signature of abc to abc(int*) or abc(int* const &). — rafix07
– rafix07, Commented Apr 25, 2019 at 7:23
adding to @darune's answer you have to use the following: std::unique_ptr<int> a = std::make_unique<int>(); abc(a); you can't initialize smart pointers like std::unique_ptr<int> a(new int); — shesharp
– shesharp, Commented Apr 25, 2019 at 7:24
@shesharp That's incorrect. Especially considering that std::make_unique wasn't introduced until the C++14 standard, while std::unique_ptr was introduced in the C++11 standard. — Some programmer dude
– Some programmer dude, Commented Apr 25, 2019 at 7:27
@Someprogrammerdude thanks for pointing that out! I thought error was due to std::unique_ptr<int> a(new int); Im used to using it with make_unique i thought it was wrong. — shesharp
– shesharp, Commented Apr 25, 2019 at 7:34

darune · Accepted Answer · 2019-04-25 07:18:47Z

1

You may pass it by const reference or reference for example:

int abc(const std::unique_ptr<int>& a)

answered Apr 25, 2019 at 7:18

darune

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