Check if array contains two specific values [duplicate]

Question

I have an array and I need to check if that array contains 2 and 3.

For example a = [1, 3].

I can do it with

a.includes(2) && a.includes(3)

I tried the following but I get inconsistent result, I don't understand why:

a.includes(1 && 3)
// true
a.includes(1 && 2)
// false
a.includes(2 && 3)
// true

Includes() cannot accept two arguments like that. You can find out more here: developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/… — Alex
– Alex, Commented May 16, 2019 at 8:02

Maheer Ali · Accepted Answer · 2019-05-16 07:58:23Z

1

a.includes(1 && 3) doesnot pass two arguments two the function. 1 && 3 is an expression which evaluates to the first falsy value value. If there is no falsy value the last value is returned. So 1 && 3 evaluates to 3

console.log(1 && 3) //3

You can use every()

[1,2].every(x => a.includes(x))

answered May 16, 2019 at 7:58

Maheer Ali

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