I've got this structure:
│
├ main.py
├ dir
| ├─ data.txt
| └─ other.py
Contents from other.py:
print(open('data.txt', 'utf-8').read())
I run main.py. It must start dir/other.py.
But other.py for works needs data.txt. Is there a way to start other.py from main.py, not editing other.py?
Note
User must be able to start other.py manualy without any errors
For this purpose you can use the import keyword. All you have to do is create an __init__.py script under the dir directory which will define the directory as a library. Then you can just use import others in the main script.
It is recommended to modify the others.py script with the below snippet
if __name__ == '__main__':
// do stuff
otherwise it will execute the library each time you import it
It is far more simple. You just have to change directory with the os.chdir("./dir") call. After that you can run a simple import and the script will be executed.
./dir/other.py:
print("Module starts")
print(open('data', 'r').read())
print("Module ends")
./main.py
print("Main start")
import os
os.chdir("./dir")
from others import other
print("Main end" )
You can import other in main file like from dir.other import *
No such file or directory: 'data.txt'
'dir/data.txt' as it is in dir directory not in same directory as main.pyother.py manually.
other.pyto be imported as a module or run as a separate process?