How to loop function inside itself and execute some of them if function name contains specific string [duplicate]

Question

I have a script define many functions. Now I want to execute some of them in a batch.

eg:

def foo_fun1():
   xxx

def foo_fun2():
   xxx

...

def bar_funx():
   yyy

I now want to loop all function and pickup some of them if the function name contains "foo", how to archive that ?

for fun in dir():
    if 'foo' in fun:
         #
         # the fun is string
         # how to call the string as function here??

Thanks!

You could try globals()[fun]() to call the function, with no arguments. — Tom Karzes
– Tom Karzes, Commented Jul 1, 2019 at 4:50
@TomKarzes It's better to avoid using globals() unless you have no other choice, and generally there are better choices. — PM 2Ring
– PM 2Ring, Commented Jul 1, 2019 at 4:55
You could put your functions into a dict, with the function name as the key. Also, a function stores its name as an attribute. In your loop you can do name = fun.__name__ — PM 2Ring
– PM 2Ring, Commented Jul 1, 2019 at 4:57
@PM2Ring Yes, it's not how I would do it, but I was directly addressing what OP was asking. — Tom Karzes
– Tom Karzes, Commented Jul 1, 2019 at 5:24

abdusco · Accepted Answer · 2019-07-01 04:53:20Z

0

You need to use globals() function, which returns a dict of every global object

def say_hey():
    print('hey')

def say_hi():
    print('hi')

def main():
    for name, func in globals().items():
        if 'say_' in name and callable(func):
            func()

if __name__ == '__main__':
    main()

which outputs

hey
hi

https://docs.python.org/3/library/functions.html#globals

answered Jul 1, 2019 at 4:53

abdusco

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