Django URL View parameter help

Question

I'm having some trouble trying to pass a string from a URL to the views. My page has user pages, and if you go to site.com/username it brings up that users page. But when I try going it says this: [invalid literal for int() with base 10: 'username'].

Here's my code:

urls.py:

(r'^user/(?P<userName>[^/]+)/$', 'mischief_blog.mischief_app.views.user_view'),

views.py:

def user_view(request, userName):
    postList = userPost.objects.filter(author=userName)
    return render_to_response('user.html', {"user": user_name, "postList": postList}, context_instance=RequestContext(request))

dting · Accepted Answer · 2011-04-17 05:59:16Z

2

get name from url:

(r'^user/(?P<userName>\w+)/$', 'mischief_blog.mischief_app.views.user_view'),

get user from name, then get posts from user: (get_object_or_404) and (User)

from django.shortcuts import get_object_or_404
from django.contrib.auth.models import User

def user_view(request, userName=None):
    user = get_object_or_404(User, username=userName)
    postList = userPost.objects.filter(author=user)
    return render_to_response('user.html', {"user": user, "postList": postList}, context_instance=RequestContext(request))

edited Apr 17, 2011 at 5:59

answered Apr 17, 2011 at 5:35

dting

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5 Comments

Sean Over a year ago

This won't work for me because I don't have a model 'User'. I'm just using the built in django user system thing.

dting Over a year ago

If you are using the default auth system you can just import the User model.

Sean Over a year ago

Oh I see, I didn't see your import statement :) sorry!

Sean Over a year ago

I have one further question. When I go to someone's profile, the url is site.com/user/username. But if I click any other link, home for example, it tries to go to site.com/user/home. How do I fix this so that it goes to site.com/home instead?

dting Over a year ago

(r^'/$', 'home', name='home') and in templates {% url home %}, sorry on my mobile. But you can post another question if it's not working.

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