Find an array that have only the not same object [duplicate]

Question

I've got an array:

var objArray = [
   { id: 0, name: ‘Object 0’, otherProp: ‘321’ },
   { id: 1, name: ‘O1’, otherProp: ‘648’ },
   { id: 2, name: ‘Another Object’, otherProp: ‘850’ },
   { id: 3, name: ‘Almost There’, otherProp: ‘046’ },
   { id: 4, name: ‘Last Obj’, otherProp: ‘984’ },
   { id: 0, name: ‘Object 0’, otherProp: ‘321’ }
];

here the id 0 add twice. I only want an array that not have the same objects.

expected output:

a = [
   { id: 0, name: ‘Object 0’, otherProp: ‘321’ },
   { id: 1, name: ‘O1’, otherProp: ‘648’ },
   { id: 2, name: ‘Another Object’, otherProp: ‘850’ },
   { id: 3, name: ‘Almost There’, otherProp: ‘046’ },
   { id: 4, name: ‘Last Obj’, otherProp: ‘984’ }]

How do I do this in JavaScript.

What should happen if a duplicate ID is used? Don't insert the entry? Remove the previous entry? — VLAZ
– VLAZ, Commented Jul 8, 2019 at 11:08
@Alexander yet it's trivial to adapt the code for arbitrary objects by comparing the property you want to consider unique (id in this case) instead of the item itself. We don't need a different question for each different case when it is all the same logic in the end. — VLAZ
– VLAZ, Commented Jul 8, 2019 at 11:32

Nina Scholz · Accepted Answer · 2019-07-08 11:16:57Z

3

You could filter the array by looking for the id in a Set.

var array = [{ id: 0, name: 'Object 0', otherProp: '321' }, { id: 1, name: 'O1', otherProp: '648' }, { id: 2, name: 'Another Object', otherProp: '850' }, { id: 3, name: 'Almost There', otherProp: '046' }, { id: 4, name: 'Last Obj', otherProp: '984' }, { id: 0, name: 'Object 0', otherProp: '321' }],
    seen = new Set,
    result = array.filter(({ id }) => !seen.has(id) && seen.add(id));

console.log(result);

answered Jul 8, 2019 at 11:16

Nina Scholz

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1 Comment

Hasibul- Over a year ago

Thanks Nina Scholz :) it's working

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