Iterate through table rows and print a href text with Python Selenium

Question

My overall goal is to iterate through every tr in this table and go through several td's per tr and print out the text in them.

I've tried going back as far as the body yet still no luck. ideally I would like to just run a forloop through table[@id='aui']/tbody/tr[i]/td[i] where i is the variable in the range(0, sizeOfTable)

ele = driver.find_elements_by_xpath("//body/div[@id='page']/section[@id='content']/div[@class='aui-page-panel']/div[@class='aui-page-panel-inner']/section[@class='aui-page-panel-content']/div[@class='aui-page-panel']/div[@class='aui-page-panel-inner']/section[@class='aui-page-panel-content']/div[@class='module']/div[@id='projects']/div[@class='p-list']/table[@id='aui']/tbody/tr[1]/td[1]")

right now when I run print(ele.text) after creating ele, it just prints out an empty list

this is the html I'm working off of:

Please paste code as text here, you can format it with the {} button, don't paste pure text content as picture here. — Tyl
– Tyl, Commented Jul 18, 2019 at 1:28

Viktoriia Kachanovska · Accepted Answer · 2019-07-18 11:01:57Z

2

Reason for the issue is a wrong XPath. The table has class with aui but not id.

Correct the XPath as below.

  //table[@class='aui']//tr

This should give you a list of rows and then you can iterate through them.

Script: if you want to print the text in the cell then use this.

rows = driver.find_element_by_css_selector("table.auti  tr")
for row in rows:
    # get the hrefs
    columsWithLink = row.find_element_by_xpath(".//td[a]")
    for column in columsWithLink:
        # print column text
        print (column.text)
        # print link href
        print(column.find_element_by_xpath(".//a").get_attribute("href"))

Script: if you just want to print link hrefs then use the below

rows = driver.find_element_by_css_selector("table.auti  tr")
for row in rows:
    # get the hrefs
    links = row.find_element_by_xpath(".//td/a")
    for link in links:
        # print link href
        print(link.get_attribute("href"))

edited Jul 18, 2019 at 11:01

Viktoriia Kachanovska

1259 bronze badges

answered Jul 18, 2019 at 3:53

supputuri

14.2k2 gold badges26 silver badges42 bronze badges

Sign up to request clarification or add additional context in comments.

8 Comments

chadlei Over a year ago

so im trying to print out the highlighted text in the html: ".com Ownership support", but in your code you jump from table to tr, dont i have to include the tbody?

supputuri Over a year ago

Not required when you are dealing with css.

supputuri Over a year ago

If you are trying to get the text associated with link, then try column.find_element_by_xpath(".//a").text and link.text respectively in the above answer.

chadlei Over a year ago

i got the text thank you! would you happen to know how to work off using a html doc instead of a url link as a webdriver? i have to log in each time to test the site so i want to skip it all

supputuri Over a year ago

Cool. If you want to load the local html doc then you can use url = r"file:///C:/Users/xxx/Desktop/sample.html" and then driver.get(url) should load the local page.

|

Collectives™ on Stack Overflow

Iterate through table rows and print a href text with Python Selenium

1 Answer 1

8 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

8 Comments

Your Answer

Sign up or log in

Post as a guest

Related