25

I try to add the legend which should, according to my example, output:

  1. a red square with the word fruit and
  2. a green square with the word veggie.

I tried several things (the example below is just 1 of the many trials), but I can't get it work.

Can someone tell me how to solve this problem?

import pandas as pd
from matplotlib import pyplot as plt
data = [['apple', 'fruit', 10], ['nanaba', 'fruit', 15], ['salat','veggie', 144]] 
data = pd.DataFrame(data, columns = ['Object', 'Type', 'Value']) 

colors = {'fruit':'red', 'veggie':'green'}           
c = data['Type'].apply(lambda x: colors[x])

bars = plt.bar(data['Object'], data['Value'], color=c, label=colors)
plt.legend()

plot

2 Answers 2

50

The usual way to create a legend for objects which are not in the axes would be to create proxy artists as shown in the legend guide

Here,

colors = {'fruit':'red', 'veggie':'green'}         
labels = list(colors.keys())
handles = [plt.Rectangle((0,0),1,1, color=colors[label]) for label in labels]
plt.legend(handles, labels)

enter image description here

Sign up to request clarification or add additional context in comments.

1 Comment

thank you, +1. @S12000 consider accepting this answer.
2

So this is a hacky solution and I'm sure there are probably better ways to do this. What you can do is plot individual bar plots that are invisible using width=0 with the original plot colors and specify the labels. You will have to do this in a subplot though.

import pandas as pd
from matplotlib import pyplot as plt

data = [['apple', 'fruit', 10], ['nanaba', 'fruit', 15], ['salat','veggie', 144]] 
data = pd.DataFrame(data, columns = ['Object', 'Type', 'Value']) 


colors = {'fruit':'red', 'veggie':'green'}
c = data['Type'].apply(lambda x: colors[x])


ax = plt.subplot(111) #specify a subplot

bars = ax.bar(data['Object'], data['Value'], color=c) #Plot data on subplot axis

for i, j in colors.items(): #Loop over color dictionary
    ax.bar(data['Object'], data['Value'],width=0,color=j,label=i) #Plot invisible bar graph but have the legends specified

ax.legend()

plt.show()

enter image description here

1 Comment

Hi, thanks. It works, I will use your solution now. However, I will just let the post open in case someone else suggest another solution as you said it's a 'hacky solution'.

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.