extern struct declaration in C

Question

I'm fairly new to C, hence could someone please help me understand the below struct declaration?

extern struct server_module* module_open (const char* module_path);

Per my understanding, module_open is pointer to the struct server_module, however, didn't understand the last part of the statement i.e. (const char* module_path)

@IgorS.K.: cdecl.org reports a syntax error for the declaration in the question. It apparently fails with named parameters. — Eric Postpischil
– Eric Postpischil, Commented Aug 29, 2019 at 17:59
@EricPostpischil You're right, looks like it does fail. But it is still a worthy tool to know about. — Igor S.K.
– Igor S.K., Commented Aug 29, 2019 at 18:26

Eric Postpischil · Accepted Answer · 2019-08-29 17:56:21Z

7

extern struct server_module* module_open (const char* module_path); declares module_open to be a function taking a parameter named module_path of type const char * and returning a struct server-module *.

answered Aug 29, 2019 at 17:56

Eric Postpischil

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1 Comment

Aniruddha Over a year ago

Thank you for your help!

ChauhanTs · Accepted Answer · 2019-08-29 18:00:09Z

1

module_open is a function which returns pointer to struct server_module

and const char* module_path is input argument type. Means function takes character string as an input extern keyword is used to tell compiler that symbol is exist in different file

answered Aug 29, 2019 at 18:00

ChauhanTs

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