Invalid argument error thrown for selenium script

Question

I have a file full of Urls (about some 3000 urls) and the requirement is to get each url invoked in a browser tab and click on each page (just the click is enough on the loaded page), which redirects to a different page. This is all I need to do.

I have written a code for the urls to retrieve one by one and clink on the page (page is designed to click anywhere to land or redirect to a different page). However, while running the code an error is being thrown with "invalid argument". Any thoughts, how can I correct the error ?

Appreciate your support.

    with open(dataFile, 'r') as urlFile:
        urlFile.readline()
        for url in urlFile:
            driver = webdriver.Chrome('C:\\chromedriver_win32\\chromedriver.exe')
            driver.get(url)
            link = driver.find_element_by_xpath("/html/body")
            link.click()
        urlFile.close()

The above code should pull each url from the file on a new browser tab and click. Repeat the same until all the urls in the file are done.

which line you are getting the error? and is there any blank lines in the text file. also, check the URL format and it should be starting link http:// or https:// — Murthi
– Murthi, Commented Sep 10, 2019 at 5:15
@Murthi, you are correct. I have the /r (carriage return) in my code and I have it removed and it is working good. Thank you for pointing this out. — user1911509
– user1911509, Commented Sep 10, 2019 at 5:38
@Murthi, I have another problem with this code. Let's say, I have n lines of Urls in the file - however, the code executes n-1 and leaves the last Urls from the file. Any suggestions, please ? — user1911509
– user1911509, Commented Sep 10, 2019 at 5:42
remove the code urlFile.readline() in the loop(second line in your code). then it will execute all the lines. — Murthi
– Murthi, Commented Sep 10, 2019 at 8:47

Tek Nath · Accepted Answer · 2019-09-10 05:22:52Z

4

I did something like this Code

from selenium import webdriver
import time


driver = webdriver.Chrome('driver_location')

f = open("dataFile.txt", 'r')
for line in f:
    driver.get(line)
    link = driver.find_element_by_css_selector("#header > div:nth-child(3) > div > div > div:nth-child(3) > div > a")
    link.click()
    print(driver.current_url)

f.close()

url in dataFile.txt file

http://automationpractice.com/index.php
http://automationpractice.com/index.php
http://automationpractice.com/index.php

output

http://automationpractice.com/index.php?controller=order
http://automationpractice.com/index.php?controller=order
http://automationpractice.com/index.php?controller=order

Hope this helps.

answered Sep 10, 2019 at 5:22

Tek Nath

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2 Comments

user1911509 Over a year ago

This worked well too. So, I have removed the /r from my code to output the urls to the file. It is working good. However, I have n lines of Urls in the file - however, the code executes n-1 and leaves the last Urls from the file. Any good suggestions, please ?

Tek Nath Over a year ago

With example above it is executing all URLs. I tried with three as shown above.

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