How to check if any element is None, or empty array, or False in a python iterable array (excluding zeros)?

Question

There is a list:

x = [5, "ce", 0, (32, "a")]

It doesn't contain a None, or empty array, or False element, so it should return True.

0 shouldn't be counted as an empty object.

y = [5, "ce", 0,, "", (32, "a")]

It contains an empty string so it should return False.

How would you do it in the fastest way?

Are you concerned about this specific list, or any list in general that may contain zero, blank string, False values, empty sublists, etc? — John Gordon
– John Gordon, Commented Sep 30, 2019 at 13:45

lmiguelvargasf · Accepted Answer · 2019-09-30 13:49:26Z

2

Use the built-in all:

>>> all(e not in [None, []] and e is not False for e in [5, "ce", 0, (32, "a")])
True
>>> all(e not in [None, []] and e is not False for e in [5, "ce", 0, 0, (32, "a")])
False

I noticed that there was a problem using e not in [None, [], False] because 0 in [None, [], False] was giving True.

edited Sep 30, 2019 at 13:49

answered Sep 30, 2019 at 13:37

lmiguelvargasf

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