I want to add float average variable inside the cout. What's the perfect way for it?
int first , second , third;
cout<<"enter the first number: ";
cin>>first;
cout<<"enter the second number: ";
cin>>second;
cout<<"enter the third number: ";
cin>>third;
cout<<float average=(first+second+third)/3;
You can't do that. Just declare the variable before printing it.
float average = (first + second + third) / 3;
std::cout << average;
What you can do, however, is just not having the variable at all:
std::cout << (first + second + third)/3;
Also note that the result of (first+second+third)/3 is an int and will be truncated. You might want to change int first, second, third; to float first, second, third; if that's not your intention.
float average=(first+second+third)/3;
cout<<average
OR
cout<<((first+second+third)/3)
You need to declare the variable type first.
You can do something like this.
int first , second , third;
cout<<"enter the first number: ";
cin>>first;
cout<<"enter the second number: ";
cin>>second;
cout<<"enter the third number: ";
cin>>third;
float average;
cout<< (average=(first+second+third)/3);
C++ way would be:
float average = static_cast<float>(first + second + third) / 3.;
std::cout << average << std::endl;
