Ruby: Check multiple keys in hash and delete it

Question

I need to check if the given both keys is present in hash. Checking is not the problem here but one of the keys may not be present and can return false. I need to delete only the keys that are present.

if model_changes.has_key?(name)
   model_changes.delete(name)
end  

if model_changes.has_key?(id)
   model_changes.delete(id)
end

Instead of writing in two separate conditions is it possible to combine and delete the present key

what if a key is not present and delete action on that particular key is called — Hemaraj
– Hemaraj, Commented Oct 22, 2019 at 6:50
@Hermaraj : From the Ruby docs for Hash#delete : Deletes and returns a key-value pair from hsh whose key is equal to key. If the key is not found, returns the default value. hence, I would simply drop the test. — user1934428
– user1934428, Commented Oct 22, 2019 at 7:24

ray · Accepted Answer · 2019-10-22 07:02:36Z

3

You can go following way,

hash = { foo: :foo, bar: :bar, meh: :meh }
output = hash.except(:meh, :bar)
# => {:foo=>:foo}

answered Oct 22, 2019 at 7:02

ray

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1 Comment

Stefan Over a year ago

Or except! to modify the hash in-place.

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