Linux bash scripting [duplicate]

Question

I have this code

echo "er453*tyu" |awk -v s=* '{print index($1,s)}'

The code prints 6. Now I want to reference 6 as a variable. E.g.

$position= "er453*tyu" |awk -v s=* '{print index($1,s)}'

Then use the variable position somewhere else in my code.

@tink read through the question! I want to reference echo "er453*tyu" |awk -v s=* '{print index($1,s)}' instead of echoing direct! — cfugus
– cfugus, Commented Dec 9, 2019 at 2:43
Write complete specs/example data. As a variable WHERE? Inside the same awk script? In an encapsulating bash script? — tink
– tink, Commented Dec 9, 2019 at 2:46

Hugo G · Accepted Answer · 2019-12-09 04:16:03Z

0

You can execute any command and save its stdout to a variable in Bash like this:

position=$(echo "er453*tyu" | awk -v s=* '{print index($1,s)}')

Some notes:

If er453*tyu is not supposed to expand, it would be safer to use single quotes around it. Same for s=*.
If you are running this within a function, declare position as a local:

local position
position=$(echo "er453*tyu" | awk -v s=* '{print index($1,s)}')

edited Dec 9, 2019 at 4:16

answered Dec 9, 2019 at 3:12

Hugo G

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2 Comments

Gordon Davisson Over a year ago

You should also have quotes around s=*, to keep the shell from trying to expand that.

Charles Duffy Over a year ago

Obvious duplicates should be closed as duplicate, not given new answers, so there's a single canonical collection of answers for each distinct question that can be as effectively vetted and edited as possible. See the "Answer Well-Asked Questions" section of How to Answer in the Help Center.

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