Facing some problems with InputMismatchException in java

Question

Here in my code, I have two String type ArrayList arr and arr2. arr ArrayList is for storing the pair of lines and here int t is for the number of pairs that user enters in arr. The Second ArrayList arr2 is for storing a single line and integer t2 is the number of a single line that a users stores in arr2. After that I have simply print arr and arr2

import java.util.Scanner;

class Main{
    public static void main(String[] args){
        Scanner sc = new Scanner(System.in);

        ArrayList<String> arr = new ArrayList<>();
        ArrayList<String> arr2 = new ArrayList<>();
        int t;
        t = sc.nextInt();

        sc.nextLine();

        for(int i=0;i<t;i++){
            String first,second;
            first = sc.nextLine();
            second = sc.nextLine();

            arr.add(first);
            arr.add(second);
        }

         sc.nextInt();
        int t2;
        t2 = sc.nextInt();

        sc.nextLine();

        for(int i=0;i<t2;i++){
            String input;
            input = sc.nextLine();
            arr2.add(input);
        }

        for(String val: arr){
            System.out.println(val);
        }
          System.out.println();
        for(String val: arr2){
            System.out.println(val);
        }

    }
}

But after entering all the input I'm getting Exception in thread "main" java.util.InputMismatchException

Sample Input-

3
ko te kader molla
tui rajakar tui rajakar
tumi ke ami ke
garo chakma bangali
jalo re jalo
agun jalo

2

jalo re jalo
ko te kader molla



Sample Output-

ko te kader molla
tui rajakar tui rajakar
tumi ke ami ke
garo chakma bangali
jalo re jalo
agun jalo

jalo re jalo
ko te kader molla

Consider using meaningful variable names. It is much easier for someone (or yourself) to follow pairsOfLines than arr2. — sleepToken
– sleepToken, Commented Jan 7, 2020 at 18:28

Frakcool · Accepted Answer · 2020-01-07 18:24:28Z

1

You're reading 2 times sc.nextInt(); after the first for-loop. In these lines:

sc.nextInt();
int t2;
t2 = sc.nextInt();

I believe your error comes from there as the next value is an int (3 in your sample input) but then you try to read another int but you're providing a String.

If this is not the issue, please post a complete Stack Trace.

answered Jan 7, 2020 at 18:24

Frakcool

11.2k10 gold badges56 silver badges94 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Facing some problems with InputMismatchException in java

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related