How to detect if mac os is up to date or outdated programmatically? [duplicate]

Question

Now I am working on mac osx app development. I need to check if os is up to date or outdated programmatically. I can see it via Software Update of System Preferences. There are a lot of solutions to get current mac os version. But I am not interested in version. Only interested in if os is the latest one or old one.

But I want to know it in my app programmatically. swift code or objective-c code is fine.

In the shell run softwareupdate --list and parse the result. — vadian
– vadian, Commented Jan 28, 2020 at 11:30
Yes, it is. But you are able to read data asynchronously from the shell with NSTask. — vadian
– vadian, Commented Jan 28, 2020 at 16:37
@vadian softwareupdate --list is helpful for me As you know, this shell command is async $ softwareupdate --list Software Update Tool Finding available software No new software available. what I want to get as result is the messages under "Finding available software". import SwiftShell do { let command = runAsync("softwareupdate", "--list") try command.finish() let result = command.stdout.read() print(result) } catch { } then the result is below Software Update Tool Finding available software I can not get "No new software available" — JS Guru
– JS Guru, Commented Jan 28, 2020 at 16:43
@vadian Could you provide me the code snippet getting full results of "softwareupdate --list"? — JS Guru
– JS Guru, Commented Jan 28, 2020 at 16:46

JS Guru · Accepted Answer · 2020-01-30 15:52:22Z

1

Below is simple code snippet but I spent a lot of time to get it done. I hope someone does not waste time like me.

import SwiftShell

func getIsOSXUpdate() -> Bool {
    // softwareupdate --list|tee
    let command = runAsync("softwareupdate", "--list")
    do {
        try command.finish()
    } catch {
        NSLog("could not collect available updates.")
        return false
    }

    let result = command.stdout.read()
    let error = command.stderror.read()

    if error.contains("No new software available") {
        return true
    }
    return false
}

edited Jan 30, 2020 at 15:52

answered Jan 28, 2020 at 19:48

JS Guru

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