Js - check if nested values of object are the same

Question

I have these nested objects. How can I check if the group_id are all the same?

console.log(getData);

{…}
    "$": function g()
    0: {…}
        DT_RowId: "row_1"
        groups: Object { group_id: 2, … }
    1: {…}
        DT_RowId: "row_2"
        groups: Object { group_id: 2, … }
    2: {…}
        DT_RowId: "row_3"
        groups: Object { group_id: 2, … }
    3: {…}
        DT_RowId: "row_4"
        groups: Object { group_id: 2, … }

A .each() provides me:

$.each( getData, function ( id, val ) {
    console.log(val.groups.group_id);
});

2
2
2
2

If getData is an array, you can use Array.every() to return true/false if every item in an array meets a given condition. — mhodges
– mhodges, Commented Feb 6, 2020 at 21:19
What is getData? Seems like it is a jQuery object?? Hard to answer without knowing what it is. — epascarello
– epascarello, Commented Feb 6, 2020 at 21:48

epascarello · Accepted Answer · 2020-02-06 21:57:25Z

Unclear what the data exactly is. If it is in array format every() is what you need, compare it to the first index value

var objData = [
  { groups: { group_id: 2 } },
  { groups: { group_id: 2 } },
  { groups: { group_id: 2 } },
  { groups: { group_id: 2 } },
  { groups: { group_id: 2 } },
]

var allMatch = objData.every((n, i, a) => n.groups.group_id===a[0].groups.group_id)

console.log(allMatch)

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/2.2.4/jquery.min.js"></script>

It seems like it might be an object in that case simple conversion can make it into an array

var objData = {
  '$': {},
  0: { groups: { group_id: 2 } },
  1: { groups: { group_id: 2 } },
  2: { groups: { group_id: 2 } },
  3: { groups: { group_id: 2 } },
  4: { groups: { group_id: 2 } },
}

var allMatch = Object.values(objData)
  .filter(o => o.groups)
  .every((n, i, a) =>
    n.groups.group_id === a[0].groups.group_id
  )

console.log(allMatch)

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/2.2.4/jquery.min.js"></script>

user9227001 · Accepted Answer · 2020-02-06 21:34:28Z

0

In the case of that being nested objects you could do something like: Object.values(getData).map(val => val.groupId).every((groupId, i, arr) => groupId === arr[0]).

answered Feb 6, 2020 at 21:34

user9227001

Comments

Sherman Hui · Accepted Answer · 2020-02-06 21:41:12Z

0

if getData is an object

  Object.keys(getData).every(key => getData[key].group_id === getData[0].group_id)

We first get the keys of the getData object container, and then we use the array of keys to access the getData object to check each obj.group_id

if getData is an array containing objects

  getData.every(obj => getData[obj].group_id === getData[0].group_id)

Similar to the above, except we can directly iterate over the array of objects

edited Feb 6, 2020 at 21:41

answered Feb 6, 2020 at 21:35

Sherman Hui

1,0183 gold badges11 silver badges22 bronze badges

3 Comments

Philipp M Over a year ago

Thanks for the help. I don't know if group_id equals 2 ... I need to check if the are all the same ...

mhodges Over a year ago

This doesn't guarantee that all the items have the same group id, this ensures that all items have the id of 2

Sherman Hui Over a year ago

Ah I misread the question, apologies. @PhilippM do you know what ID you'd like to check for? I've updated it to just make sure that it matches the first group's group_id

Addis · Accepted Answer · 2020-02-06 21:42:43Z

0

You can use Object.keys to iterate though the object and use every to test all values satisfy the condition.

const nestedObj = {
    0: {
        DT_RowId: "row_1",
        groups: { group_id: 2}
    },
    1: {
        DT_RowId: "row_2",
        groups: { group_id: 2}
    },
    2: {
        DT_RowId: "row_3",
        groups: { group_id: 2}
    },
    3: {
        DT_RowId: "row_4",
        groups: { group_id: 2}
    }    

}

const GROUP_ID = nestedObj[0].groups.group_id;
const isGroupIdSame = Object.keys(nestedObj).every(key => nestedObj[key].groups.group_id === GROUP_ID);

console.log(isGroupIdSame)

answered Feb 6, 2020 at 21:42

Addis

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