Looking to do something like in C#:
bool walkable = t.Type == TileType.Green ? true : false;
but in Java
Boolean international_F = (in.next() == 'Y') ? true : false;
The above is what I've tried so far. Wondering if it's even possible.
EDIT: I just noticed .nextChar() doesn't exist. Edited snippet to reflect that.
"nextChar": Assuming in is a Scanner, your issue is that Scanner doesn't have a nextChar() method. You could read a whole word, and then take it's first char:
char theChar = in.next().charAt(0)
boolean vs ternery: If your outputs are true/false, then you don't need an if. You can just write:
bool walkable = t.Type == TileType.Green; // C#
boolean international_F = in.next().charAt(0) == 'Y'` // Java
boolean vs Boolean: Please also note that boolean is the primitive boolean type in Java. Using Boolean will force it to be wrapped as the Boolean class.
case sensitivity: If you want to allow 'y' or 'Y', force the input to a known case first. Since charAt() returns primitive char, you need to use the static Character.toUpperCase().
boolean isY = Character.toUpperCase(in.next().charAt(0)) == 'Y'
// - OR -
boolean isY = in.next().startsWith("Y") // not case-insensitive
Boolean international_F = "Y".equals(in.next()); // next returns a string
Boolean international_F =in.next().charAt(0) == 'Y';
in.next().startsWith("Y").
You do not need a ternary operator to simply assign the result (true/false) of the evaluation of the condition. You need a ternary operator if you want to do something based on the result of the evaluation of the condition e.g.
import java.util.Scanner;
public class Main {
public static void main(String[] args) throws Exception {
Scanner in = new Scanner(System.in);
System.out.print("Do you want to continue? [Y/N]: ");
boolean yes = in.nextLine().toUpperCase().charAt(0) == 'Y';
if (yes) {
System.out.println("You have chosen to continue");
} else {
System.out.println("You have chosen to stop");
}
// Or simply
System.out.print("Do you want to continue? [Y/N]: ");
if (in.nextLine().toUpperCase().charAt(0) == 'Y') {
System.out.println("You have chosen to continue");
} else {
System.out.println("You have chosen to stop");
}
// You can use ternary operator if you want to do something based on the result
// of evaluation of the condition e.g.
System.out.print("Do you want to continue? [Y/N]: ");
String response = in.nextLine().toUpperCase().charAt(0) == 'Y' ? "Yes" : "No";
System.out.println(response);
// Without a ternary operator, you would write it as:
System.out.print("Do you want to continue? [Y/N]: ");
String res;
char ch = in.nextLine().toUpperCase().charAt(0);
if (ch == 'Y') {
res = "Yes";
} else {
res = "No";
}
System.out.println(res);
}
}
A sample run:
Do you want to continue? [Y/N]: y
You have chosen to continue
Do you want to continue? [Y/N]: n
You have chosen to stop
Do you want to continue? [Y/N]: y
Yes
Do you want to continue? [Y/N]: n
No
This is an example demonstrating what you want to do:
char a = 'a';
char b = 'b';
Boolean b1 = (a == 'a') ? true : false;
Boolean b2 = (a == b) ? true : false;
System.out.println(b1);
System.out.println(b2);
The output will be:
true
false
bool international_F = n.next() == 'Y';though?in? Otherwise the syntax is correct. You can totally do that.