Warning: A non-numeric value encountered in php time script

Question

I am generating drop down list to show 15 minutes duration till 6 hrs it will generate like 15 minutes ,30 minutes,45 minutes but I am getting error non numeric value encountered so I followed below links but It didn't solved my issue

links Refer:

date() method, "A non well formed numeric value encountered" does not want to format a date passed in $_POST

A non well formed numeric value encountered - Error in PHP

<?php 

echo "<select>";

for($i = 0; $i <= 6; $i++){
    for ($j = 0; $j <= 45; $j +=15){
        if ($i === 0 && $j === 0){
            //do nothing
        }
        else{
            //get string for hours
            switch($i){
                case 0:
                    $hours = "";
                    break;
                case 1:
                    $hours = "1 hour";
                    break;
                default:
                    $hours = $i . " hours";
                    break;
            }

            //get string for minutes
            switch($j){
                case 0:
                    $minutes = "";
                    break;
                default:
                    $minutes = $j . " minutes";
                    break;
            }

            $value = ($hours * 60) + $minutes;



            //output
            echo "<option value='" . $value . "'>" . $hours . " " . $minutes . "</option>";
        }
    }
}

echo "</select>";

?>

You are setting strings and then trying to do multiplication. For example $hours = "1 hour"; -- cannot be multiplied by 60. — Jeremy Harris
– Jeremy Harris, Commented Feb 11, 2020 at 14:26
Don't try to multiply "1 hour" by 60. Change your code to only handle numbers in your loops, and then worry about how to display it AFTER you calculate. — Jeremy Harris
– Jeremy Harris, Commented Feb 11, 2020 at 14:33

Funk Forty Niner · Accepted Answer · 2020-02-11 14:37:43Z

2

It was mistake which I did in code as suggested by @Jeremy Harris

Intval() solved my issue

$value = (intval($hours) * 60) + intval($minutes);

edited Feb 11, 2020 at 14:37

Funk Forty Niner

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answered Feb 11, 2020 at 14:34

msp

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