Extracting part of the email address by using Python regular expression

Question

I have the following string:

'[email protected], [email protected], [email protected], [email protected]'

I want to extract com, gov, com, bi.

I wrote (?<=@)\w+ regex, but it turn out to extract yahoo,est,ywuancjds,ililsa. I don't know how to include the vocabulary behind @.

Regarding est.gov.cn -> gov. Do you want a.b.c.d to return only c then too? — Alex Telon
– Alex Telon, Commented Apr 2, 2020 at 11:08

Wiktor Stribiżew · Accepted Answer · 2020-04-02 11:09:21Z

2

You may use

re.findall(r'@[^\s.]+\.(\w+)', text)

See the regex demo and the Python demo

Details

@ - a @ char
[^\s.]+ - 1 or more chars other than whitespace and a dot
\. - a dot
(\w+) - Group 1 (the value captured in this group will only be returned by re.findall): one or more word chars.

Python demo snippet:

import re
text = "[email protected], [email protected], [email protected], [email protected]"
print( re.findall(r"@[^\s.]+\.(\w+)", text) )
# => ['com', 'gov', 'com', 'bi']

edited Apr 2, 2020 at 11:09

answered Apr 2, 2020 at 11:02

Wiktor Stribiżew

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2 Comments

user13196723 Over a year ago

I am also wondering if I only want the email address in odd order, how could I write it?

Wiktor Stribiżew Over a year ago

@user13196723 Sorry, not sure what you mean.

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