I have a dictionary with four keys a,b,c,d with values 100,200,300,400
list1 = {'a':'100','b':'200','c':'300','d':'400'}
And a variable inputs.
inputs = 'c'
If inputs is c. The list1 dictionary has to be sorted based on it.
inputs = 'c'
list1 = {'c':'300','a':'100','b':'200','d':'400'}
inputs = 'b'
list1 = {'b':'200','a':'100','c':'300','d':'400'}
In Python3.7+ dict keys are stored in the insertion order
k ='c'
d={k:list1[k]}
for key in list1:
if key!=k:
d[key]=list1[key]
Output
{'c': '300', 'a': '100', 'b': '200', 'd': '400'}
Seems like you just want to rearrange your dict to have the chosen value at the front, then the remaining keys afterwards:
dict1 = {'a':'100','b':'200','c':'300','d':'400'}
key = 'c'
result = {key: dict1[key], **{k: v for k, v in dict1.items() if k != key}}
print(result)
# {'c': '300', 'a': '100', 'b': '200', 'd': '400'}
The ** simply merges the leftover filtered keys with key: dict1[key].
If you just want to change the position to the first one a given value if it exists, it could be done in the following way:
list1 = {'a':'100','b':'200','c':'300','d':'400'}
inputs = 'c'
output = {}
if inputs in list1.keys():
output[inputs] = list1.get(inputs)
for i in list1.keys():
output[i] = list1[i]
Output;
{'c': '300', 'a': '100', 'b': '200', 'd': '400'}
Here's a one-liner:
d = {'a':'100','b':'200','c':'300','d':'400'}
i = input()
d = {i:d[i],**{k:d[k] for k in d if k!=i}}
print(list1)
Input:
c
Output:
{'a': '100', 'b': '200', 'd': '400', 'c': '300'}
