Printing output only once inside the loop

Question

for i in os.listdir(path_1):
    for j in os.listdir(path_2):
        file_name = (j.split('.')[0])
        if i.__contains__(file_name) and i.endswith('txt'):
            txt_tym = os.path.getctime(path_1 + '/' + i)
            log_tym = os.path.getctime(path_2 + '/' + j)
            if txt_tym >= log_tym:
                print('Issues found in: '+i)
            else:
                print('No issues found')

I'm using this program to compare timestamp between two files in two different directory, it has same names but different extension,
I need to show the result in a text document.If there is an issue it will print Isues found in: filename.
I need to print No issues found only if there is no single files with the issue,
Im using else inside the loop and it prints multiple times.
Please give some suggestions to this

... create a list, add all issue-file-names to the list, print the list outside the loop - if list empty print your No issue message — Patrick Artner
– Patrick Artner, Commented May 17, 2020 at 17:40

user2740650 · Accepted Answer · 2020-05-17 17:42:56Z

1

Something like this should work:

issues_found = false
for i in os.listdir(path_1):
    for j in os.listdir(path_2):
        file_name = (j.split('.')[0])
        if i.__contains__(file_name) and i.endswith('txt'):
            txt_tym = os.path.getctime(path_1 + '/' + i)
            log_tym = os.path.getctime(path_2 + '/' + j)
            if txt_tym >= log_tym:
                print('Issues found in: '+i)
                issues_found = true

if not issues_found:
    print('No issues found')

answered May 17, 2020 at 17:42

user2740650

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2 Comments

JoJo Over a year ago

Thank you so much!!

user2740650 Over a year ago

You're welcome. Please accept the answer if it helped you.

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