How to sort 2D list elements in python?

Question

I need to know how to sort the list elements in python without changing their position.

    a = [[5, 4, 5], [4, 5, 6], [2, 8, 2], [5, 2, 2]]
    b = [[3, 2, 4], [3, 6, 7], [3, 6, 0], [7, 2, 1]]
    c = [[x + y for x, y in zip(s1, s2)] for s1, s2 in zip(a, b)]
    c.sort(key=lambda x: x[1])
    c.reverse()
    for c in c:
        print(c)

I tried using the lambda but it sorts them by the first number, thus changing the order. I need to sort array c so it would look something like this:

Input: c = [[5, 4, 5], [4, 5, 6], [2, 8, 2], [5, 2, 2]]
Output: c = [[4, 5, 5], [4, 5, 6], [2, 2, 8], [2, 2, 5]]

I hope i made myself clear enough, any help is appreciated

Cory Kramer · Accepted Answer · 2020-05-26 11:22:41Z

3

You can do this in your original list comprehension using sorted on the inner list comprehension.

>>> [sorted(i+j for i, j in zip(s1, s2)) for s1, s2 in zip(a, b)]
[[6, 8, 9], [7, 11, 13], [2, 5, 14], [3, 4, 12]]

answered May 26, 2020 at 11:22

Cory Kramer

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Alexander Lekontsev · Accepted Answer · 2020-05-26 11:21:22Z

2

for item in a:
    item.sort()

answered May 26, 2020 at 11:21

Alexander Lekontsev

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Amos Egel · Accepted Answer · 2020-05-26 11:22:37Z

2

You could try this:

c = [sorted(x) for x in a]

answered May 26, 2020 at 11:22

Amos Egel

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