Replace a string in a list with a list of strings using a dictionary

Question

I am attempting to replace the first string in the following list using the subsequent dictionary that is mapping to a list of strings.

id_list = ['40000', '58962', '85496']
id_dict = {'10000': ['10001','10002','10003'], '40000': ['40001','40002','40003']}

Using a defined function such as this:

def find_replace_multi_ordered(string, dictionary):
    # sort keys by length, in reverse order
    for item in sorted(dictionary.keys(), key = len, reverse = True):
        string = re.sub(item, dictionary[item], string)
    return string

# Credit: http://pythoninthewyld.com/2018/03/12/dict-based-find-and-replace-deluxe/

In the following for loop:

for i in id_list:

    if id_list[0][-4:] == '0000':
        id_list.replace(find_replace_multi_ordered(i, id_dict))

    else:
        pass

print(id_list)

This works for string to string dictionary mapping but results in a TypeError for sting to list mapping.

Error:

TypeError: unhashable type: 'list'

The desired output would be the following:

id_list = [['40001','40002','40003'], '58962', '85496']

Thank you for any and all recommendations!

What happens if you type id_dict['4000']?

Gaslight Deceive Subvert
– Gaslight Deceive Subvert

2020-05-28 21:26:47 +00:00
Commented May 28, 2020 at 21:26 — Gaslight Deceive Subvert
– Gaslight Deceive Subvert, Commented May 28, 2020 at 21:26

azro · Accepted Answer · 2020-05-28 21:27:52Z

2

There is much more easy, or each value of the list, if it's in the dict just replace by the pointed value, if it's absent keep the value

Detail of id_dict.get(item, item)

first item is the key to look at, to retrieve a value
second item is the default value, if the key has not been found

id_list = ['40000', '58962', '85496']
id_dict = {'10000': ['10001','10002','10003'], '40000': ['40001','40002','40003']}

id_list = [id_dict.get(item, item) for item in id_list]
print(id_list) # [['40001', '40002', '40003'], '58962', '85496']

answered May 28, 2020 at 21:27

azro

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Comments

Alireza · Accepted Answer · 2020-05-28 21:31:21Z

0

Does it do what you want?

id_list = ['40000', '58962', '85496']
id_dict = {'10000': ['10001','10002','10003'], '40000': ['40001','40002','40003']}

X = [
    item if item not in id_dict else id_dict[item] for item in id_list
]
print(X) # [['40001', '40002', '40003'], '58962', '85496']

answered May 28, 2020 at 21:31

Alireza

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