The list are below
second_list = ['C']
first_list = ['A', 'B']
third_list = ["D"]
Expected out is below
the firstlist is A,B the second_list is C and thirdlist is D
psudo code
print (f'the firstlist is {j for j in first_list } the second_list is {for j for j in second_list} and thirdlist is {for j for j in third_list')
you can use join
second_list = ['C']
first_list = ['A', 'B']
third_list = ["D"]
print (f'the firstlist is {",".join(first_list)} the second_list is {",".join(second_list)} and thirdlist is {",".join(third_list)}')
the firstlist is A,B the second_list is C and thirdlist is D
Your pseudo-code is very close but you're better off using string.join to create the comma-separated lists (the expressions in f-strings can be arbitrarily complex):
second_list = ['C']
first_list = ['A', 'B']
third_list = ["D"]
print (f'the firstlist is {",".join(first_list)} the second_list is {",".join(second_list)} and thirdlist is {",".join(third_list)}')
Output:
the firstlist is A,B the second_list is C and thirdlist is D
