Python parse a String value and load into a Dictionary

Question

I need to parse a string value and load into a python dictionary

Input:

attributes = "LIFETIME=203421,ID=acr44,SCOPE=[open,basic.operation:read,common.operation:write],USER=b611-410e,CLAIMS_"

Expected Output :

attributesDictionary = { "LIFETIME" : "203421",
                         "ID" : "acr44",
                         "SCOPE" : "[open,basic.operation:read,common.operation:write]",
                         "USER" : "b611-410e",
                         "CLAIMS_" : None
                         }

attributesDictionary["ID"]
>>> 'acr44'

attributesDictionary["SCOPE"]
>>> '[open,basic.operation:read,common.operation:write]'

I am new to python programming. How can we achieve this ?

Tried using python regex to identify a key value pair separated by '=' . But it is not working for all scenarios — RaAm
– RaAm, Commented Jul 6, 2020 at 10:14
Could you show the exact code you tried, and an example scenario where it doesn't work? — Karl Knechtel
– Karl Knechtel, Commented Jul 6, 2020 at 10:18
If you create the source line, save it to json and then read from json. — Evgeniy_Burdin
– Evgeniy_Burdin, Commented Jul 6, 2020 at 10:19
@Evg I am not creating the source line, it is coming as a string value from a gateway. — RaAm
– RaAm, Commented Jul 6, 2020 at 10:21

Chris · Accepted Answer · 2020-07-06 10:25:25Z

6

One way using re.split:

import re

d = {}
for k in re.split(",(?![^\[]*\])", attributes):
    key, *val = k.split("=", 1) 
    d[key] = val[0] if val else None
d

Output:

{'CLAIMS_': None,
 'ID': 'acr44',
 'LIFETIME': '203421',
 'SCOPE': '[open,basic.operation:read,common.operation:write]',
 'USER': 'b611-410e'}

answered Jul 6, 2020 at 10:25

Chris

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2 Comments

RaAm Over a year ago

can you please explain me this regex (?![^[]*])

Chris Over a year ago

@RaAm. It is looking for , to split but not if (i.e. negative lookahead (?!) it is inside a part that starts with [, and anything (*) until ].

Manan Gajjar · Accepted Answer · 2020-07-06 10:31:46Z

0

Not sure but here I observed a pattern that all the keys are in capital letter. If that is the case, You can do the following,

import re

attributes = "LIFETIME=203421,ID=acr44,SCOPE=[open,basic.operation:read,common.operation:write],USER=b611-410e,CLAIMS_"

keys = re.findall("[A-Z]+", attributes)
values = re.findall("[^A-Z=]+,", attributes)
attributesDictionary = dict(zip(keys,values))

this will give you the following output,

{'LIFETIME': '203421',
 'ID': 'acr44',
 'SCOPE': '[open,basic.operation:read,common.operation:write]',
 'USER': 'b611-410e',
 'CLAIMS': '_'}

edited Jul 6, 2020 at 10:31

answered Jul 6, 2020 at 10:24

Manan Gajjar

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