PHP Unit - Mock Class

Question

How to mock class method getResult() ?

use App\ExampleClass;


$res = ExampleClass::getResult();

What I tried so far, and it didn't work:

$this->exampleClass = $this->getMockBuilder('App\ExampleClass')
    ->disableOriginalConstructor()
    ->getMock();


$this->exampleClass->expects($this->once())
    ->method('getResult')
    ->willReturn(true);

Mocking static methods seems to have been possible but also seems to have been removed, stackoverflow.com/questions/2357001/… and github.com/sebastianbergmann/phpunit-documentation/issues/77 give more info. — Nigel Ren
– Nigel Ren, Commented Jul 6, 2020 at 10:34
Mocking static methods is not supported: phpunit.readthedocs.io/en/9.2/test-doubles.html "Please note that final, private, and static methods cannot be stubbed or mocked. They are ignored by PHPUnit’s test double functionality and retain their original behavior except for static methods that will be replaced by a method throwing a \PHPUnit\Framework\MockObject\BadMethodCallException exception." — Philip Weinke
– Philip Weinke, Commented Jul 6, 2020 at 11:48

t_dom93 · Accepted Answer · 2020-07-06 14:01:42Z

1

PHPUnit will ignore mocking static methods:

Please note that final, private, and static methods cannot be stubbed or mocked. They are ignored by PHPUnit’s test double functionality and retain their original behavior except for static methods that will be replaced by a method throwing a \PHPUnit\Framework\MockObject\BadMethodCallException exception.

https://phpunit.readthedocs.io/en/9.2/test-doubles.html?highlight=static#test-doubles

You can't do it with PHPUnit’s phpunit-mock-objects library. Seek to the alternative - Mockery:

$this->exampleClassMock = \Mockery::mock('overload:App\ExampleClass');

$this->exampleClassMock
  ->shouldReceive('getResult')
  ->once()
  ->andReturn(true);

answered Jul 6, 2020 at 14:01

t_dom93

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1 Comment

Sebastian Bergmann Over a year ago

You cannot use phpunit-mock-objects with current versions of PHPUnit.

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