how to call function in executable from my library?

Question

I have an executable and a dynamic library (.so). The library exports some symbols and executable calls it successfully. But I want to make possible to library call executable's functions. I've tried to do following in executable:

//test
extern "C" void print(const char * str) {
    std::cout << str << std::endl;
}

and this in library:

extern "C" void print(const char *);

but when i call dlopen in executable (to load the library) it returns error undefined symbol: print. how can i fix it?

Pubby · Accepted Answer · 2016-07-15 04:21:51Z

14

In Linux/ELF you can pass the -export-dynamic option to the linker (-rdynamic on the compiler driver gcc) so symbols from the executable are exported to shared objects.

You'd have a dummy print implementation in your library, which would be shadowed by the implementation on your executable, since the executable is usually searched before shared objects for symbol resolution.

This has the disadvantage that it's not very fine-grained, you could end up overriding some symbol you didn't intend to. The finer-grained option would be to create a list of symbols to be exported as:

{
    print;
    <other symbols>
};

and pass that list to the linker, e.g. from gcc: -Wl,--dynamic-list=<file with list of symbols>

edited Jul 15, 2016 at 4:21

Pubby

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answered Jun 9, 2011 at 19:52

ninjalj

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3 Comments

ninjalj Over a year ago

@milo: I've added a more fine-grained way of exporting symbols from the executable.

milo Over a year ago

thanks a lot! i think i'd better read "dso howto" to get more comprehesive knowledges in shared objects.

ManuelSchneid3r Over a year ago

A few word to the other major platforms would be nice.

Hasturkun · Accepted Answer · 2011-06-09 12:11:29Z

4

An easier way to achieve this is to have the executable register a function for later use by the library, the library stores a pointer to the function, and may call it at a later time.

answered Jun 9, 2011 at 12:11

Hasturkun

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