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this is my code and I'm not sure why I'm getting an error whenever I try to test it. It keeps saying return value ignored with scanf


#include <stdio.h>
#include <math.h>


int main(void) {

    float money, tax, result;

    printf("Enter the amount of money.");
    scanf("%f", &money);

    tax = 0.05 * money;

    result = tax + money;

    printf("With tax added: $%f", result);

    return 0;
}
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    Try for example to enter abc instead of a number when prompted, and see what happens next. That's one error case that checking the return value of scanf would catch. Commented Aug 24, 2020 at 22:23

1 Answer 1

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5

It is because return value is ignored.

You should check return values of scanf() to check if readings are successful.

#include <stdio.h>
#include <math.h>


int main(void) {

    float money, tax, result;

    printf("Enter the amount of money.");
    if (scanf("%f", &money) != 1) {
        fputs("read error!\n", stderr);
        return 1;
    }

    tax = 0.05 * money;

    result = tax + money;

    printf("With tax added: $%f", result);

    return 0;
}
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