Python Json Parsing

Question

I'm having a bit of an issue with parsing json with python using the json library. Here is the format of the json I'm trying to parse:

{'entry':[
    {

        JSON Data 1
    }, 

        JSON Data 2
    }
]}

And here is my Python:

for entry in response['entry'][0]:

    video['video_url'] = entry['id']['$t']
    video['published'] = entry['published']['$t']

I don't seem to be able to iterate over the two blocks of JSON with the above code, I only get the first block outputted for some reason.

Anybody have any ideas?? Thanks in advance.

You seem to be missing a { in your JSON. (As if you'd be missing a bracket in Python.) — Chris Lutz
– Chris Lutz, Commented Jun 20, 2011 at 10:31

Artsiom Rudzenka · Accepted Answer · 2011-06-20 10:31:19Z

1

If:

response = {'entry':[
    {

        JSON Data 1
    }, 
    {

        JSON Data 2
    }
]}

And:

response['entry'][0] == { JSON Data 1  }

Then:

for entry in response['entry']:

    video['video_url'] = entry['id']['$t']
    video['published'] = entry['published']['$t']

Or:

video = dict(zip(['video_url', 'published'], [entry['id']['$t'], entry['published']['$t']]) for entry in response['entry']

answered Jun 20, 2011 at 10:31

Artsiom Rudzenka

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3 Comments

user179169 Over a year ago

Nope, that only returns the first block :-/ Thanks for your help

user179169 Over a year ago

response['entry'][0] == { JSON Data 1 }, {JSON Data 2}

Artsiom Rudzenka Over a year ago

Ok, than could you please give us your input in details so we will able to understand what you really need? response['entry'][0] == { JSON Data 1 }, {JSON Data 2} or response['entry'][0] == [{ JSON Data 1 }, {JSON Data 2}]?

Ignacio Vazquez-Abrams · Accepted Answer · 2011-06-20 10:31:08Z

1

That list contains 2 separate dicts. Iterate over the list directly.

answered Jun 20, 2011 at 10:31

Ignacio Vazquez-Abrams

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2 Comments

user179169 Over a year ago

could you provide an example please?

Ignacio Vazquez-Abrams Over a year ago

for foo in [1, 2, 3]: do_something(foo)

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