def recur(y):
if y>0:
print(y)
recur(y-1)
print("all the recursive calls are done, now printing the stack") # I want this statement printed only once
print(y)
recur(5)
I want the print statement to be printed only once. I don't want to use if y>4 print() that defect the purpose.
I want the output to be like this:
5
4
3
2
1
all the recursive calls are done, now printing the stack
1
2
3
4
5
Put the message in the else: block so it's only printed when we don't recurse.
def recur(y):
if y>0:
print(y)
recur(y-1)
print(y)
else:
print("all the recursive calls are done, now printing the stack")
recur(5)
when you reach the stop condition print the required text:
def recur(y):
if y>0:
print(y)
recur(y-1)
print(y)
else:
print("all the recursive calls are done, now printing the stack")
def recur(y):
if y > 0:
print(y)
recur(y - 1)
if y == 1:
print("all the recursive calls are done, now printing the stack") # I want this statement printed only once
print(y)
recur(5)
prints
5
4
3
2
1
all the recursive calls are done, now printing the stack
1
2
3
4
5
because it only prints at the end of recursion, where y == 1. If you do recursion where 1 isn't the end, all you need to do to create a similar effect is to locate where the final recursion is and then put a print statement in that will only activate if you're in the final recursion.
