In the following example, print statement is evaluated with the output "test".
x = [3]
if x != 3:
print("test")
But I don't understand how this works. Is the value x assigned to the address of the list [3] and therefore x != 3 evaluates to True? Because my intuition says that I should get an Error here since you can't compare a list to an int.
The Python documentation on Comparisons states in part:
Objects of different types, except different numeric types, never compare equal. The
==operator is always defined but for some object types (for example, class objects) is equivalent to is. The<,<=,>and>=operators are only defined where they make sense; for example, they raise aTypeErrorexception when one of the arguments is a complex number.
Hence, Python will let you use == and != between any two types, but in the case of comparing a list to an integer, they will never compare equal.
collections.defaultdict and dict can compare equal because one inherits from the other, but they're different types all right. That's not a critic of your answer, but rather of the documentation.__eq__ and __ne__
3 != [3]is true, because they're different types.False == 0 == 0.0