Subtract datetime in python

Question

I am trying to calculate time between two peaks. Let suppose the first peak appear at 31 seconds and 56 milliseconds. The second peak appears at 32 second and 37 milliseconds. I can simply subtract 32.37-31.56, which is around 0.8. What if the first peak appears at 59.32 seconds, and a second peak at 00.32 of the next minute. How can I subtract this? So I have to incorporate minutes. I used datetime.now().strftime("%M:%S.%f") to get minutes, seconds and milliseconds. The output is a string such as '49:31.566308'. How I can subtract it from '49:32.069660' I tried to subtract two date-time like the following but failed

x=datetime.now().time()
sleep(2)
datetime.now().time()-x

I got this error

TypeError: unsupported operand type(s) for -: 'datetime.time' and 'datetime.time'

Have you tried using time.time() values, which are just seconds since 1970 as a floating point? (or in python3 better to use time.monotonic() in case daylight savings or leap seconds happen during run of program). — Andrew Allaire
– Andrew Allaire, Commented Nov 6, 2020 at 22:14

Challe · Accepted Answer · 2020-11-06 22:14:43Z

3

You can't subtract the datetime.time() objects from each other, but you can substract the datetime.datetime() objects to create datetime.timedelta() which contains the data you want.

For example

x = datetime.now()
sleep(2)
(datetime.now() - x).seconds
(datetime.now() - x).microseconds

answered Nov 6, 2020 at 22:14

Challe

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Gabio · Accepted Answer · 2020-11-06 22:16:51Z

2

Try:

from datetime import datetime
import time

x = datetime.now()
time.sleep(2)
diff = datetime.now() - x
print(f"{diff.seconds}.{diff.microseconds}")  # 2.2469

answered Nov 6, 2020 at 22:16

Gabio

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