In my project, ID is designed as snowflakeid. The front end passes a string to me, and the database storage is bigint. This means that before I store it, it needs to be converted to uint. Please tell me what to do? demo data :
m := "156343853366906880"
u, _ := strconv.ParseUint(m, 0, 19)
The expected results are accurate and will not lose accuracy
Third parameter of strconv.parseUint() is bitSize. 19 bits are not sufficient to represents the number 156343853366906880. So the method returns an error. (which you are ignoring by assigning it to _)
m := "156343853366906880"
_, err := strconv.ParseUint(m, 0, 19)
fmt.Println(err)
//strconv.ParseUint: parsing "156343853366906880": value out of range 524287
2^19 - 1 = 524287 is the biggest unsigned number that can be represented with 19 bits.
Pass 64 as bitSize :
m := "156343853366906880"
u, err := strconv.ParseUint(m, 0, 64)
if err == nil {
fmt.Print(u)
//156343853366906880
}
If your number is going to greater than uint64 use big.Int :
SnowflakeID is a time based 64-bit unique id. Since you need to convert string to a 64-bit number, strconv.ParseUint() is quite good. See, the reference at ParseUint.
In your code, you used 19 as bit size. Do not mix it with the number of digit(s) in the integer (unsigned) represented by the string from frontend.
For convert a 64-bit SnowflakeID (string) into a 64-bit unsigned integer, use 64 as bitSize arg.
U, err := strvonv.ParseUint(s, 0, 64)
if err != nil {
// handle error...
}
Also do not try to ignore error, when it really matters.
