I have a numerical list which looks like ['3,2,4', '21,211,43', '33,90,87']
I guess at this point the elements are considered as strings.
I want to remove the inverted comas and to make a list which with all these numbers.
Expected output is [3,2,4, 21,211,43, 33,90,87]
Also, I would like to know if the type of element is converted from to string to integer.
Somebody please help me!
What about the following:
result = []
# iterate the string array
for part in ['3,2,4', '21,211,43', '33,90,87']:
# split each part by , convert to int and extend the final result
result.extend([int(x) for x in part.split(",")])
print(result)
Output:
$ python3 ~/tmp/so.py
[3, 2, 4, 21, 211, 43, 33, 90, 87]
-. If you just skip them, then int(x) for x in part.split(",") if x != "-" should be enough. If you want to make them 0s then you can just use part.replace("-", "0") before splitting. Finally, if you want to convert them to None, I would expand the generator into a second for-loop and use try/except to set to None all the values that were not intsThere are 3 moving parts here:
First one, str.split:
>>> '1,2,3'.split(',')
['1', '2', '3']
Second one int:
>>> int('2')
2
And last but not least, list comprehensions:
>>> list_of_lists = [[1,2],[3,4]]
>>> [element for sublist in list_of_lists for element in sublist]
[1, 2, 3, 4]
Putting all three parts together is left as an exercise for you.
>>> your_list = ['3,2,4', '21,211,43', '33,90,87']
>>> your_list = [int(num) for item in your_list for num in item.split(",")]
>>> print(your_list)
[3, 2, 4, 21, 211, 43, 33, 90, 87]
[int(x) for string in data for x in string.split(',')]