While Loop stop with blank input

Question

How can I make the while loop stop when the x input is blank instead of it stopping when the word 'stop' appears?

This is what I did but with 'stop'. However if I change the condition to x!=' ', when I try to convert x into an int it breaks.

x=''
y=''
list=[]
while x!='stop':
    x=input('x input: ')
    y=int(input('y input: '))
    if x!='stop':
        list.append((int(x),y))
    
print('Stop')
print(list)

jastor_007 · Accepted Answer · 2020-11-28 13:26:41Z

1

Try this

x=''
y=''
list=[]
while x!='stop':
    x=input('x input: ')
    y=int(input('y input: '))
    # break loop when x is empty string
    if x == '':
        break;
    if x!='stop':
        list.append((int(x),y))
    
    
print('Stop')
print(list)

break keyword breaks the loop if x is empty string. Validate variable x before casting it to int.

answered Nov 28, 2020 at 13:26

jastor_007

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2 Comments

Abhishek Rai Over a year ago

@bench You should accept the answer by clicking the grey tick under the vote sign. If you feel like, you can give an upvote as well. Helps the rep of the person who answered.

fiona Over a year ago

Just did! I forgot to do it cause it made me wait 5 minutes

talismanbrandi · Accepted Answer · 2020-11-28 13:34:21Z

1

This should do what you want to do.

x='x'  
y='y'  
list=[]  
while x!='':  
    x=input('x input: ')  
    if x!='':  
        y=int(input('y input: '))  
        list.append((int(x),y))  
    
print('Stop')  
print(list)

answered Nov 28, 2020 at 13:34

talismanbrandi

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