split string into multiple lists by a char

you can use split

 l = "& True  True & True  False & False"
 result = [j.split() for j in l.split('&') if j!='']
 print(result)

output

[['True', 'True'], ['True', 'False'], ['False']]

With regex:

import re
s = "& True  True & True  False & False"
out = [list(map(eval, i.split())) for i in re.findall("&?([^&]+)&?", s)]

gives

[[True, True], [True, False], [False]]

As it is known, eval is dangerous so if you actually want the boolean values, use ast.literal_eval in place of eval as the safest choice, or you can have a dirty lambda inside like this:

[list(map(lambda x: x == 'True', i.split())) for i in re.findall("&?([^&]+)&?", s)]

and dont forget to cast it to bool:

mystr = "& True  True & True  False & False"
l = [[s == 'True' for s in t.strip().split()] for t in mystr.strip('&').split('&')]
>>> l
[[True, True], [True, False], [False]]

You can use split method of string

yourstring.split("&")

see this , it can be helpfull for you .

https://www.w3schools.com/python/ref_string_split.asp

Another way to do it with filter, map and split,

string = '& True True & True False & False'
required = list(filter(None,map(str.strip, string.split('&'))))
result = [l.split() for l in required]
print(result)

Result:

[['True', 'True'], ['True', 'False'], ['False']]