Breaking While Loop for multiple inputs of list...for nested list

Question

Hi I'm trying to get multiple inputs in the form of a list, which is nested inside a list. I'm able to get the output but not able to break out from the loop.

values = []
while True:
    val = list(input("Enter an integer, the value ends if it is 'stop': "))
    if val == 0:
        exit()
    values.append(val)
    print(values)

I even used break..after the if condition..no Joy !!

Enter an integer, the value ends if it is 'stop': 4569
[['4', '5', '6', '9']]
Enter an integer, the value ends if it is 'stop': 666655
[['4', '5', '6', '9'], ['6', '6', '6', '6', '5', '5']]
Enter an integer, the value ends if it is 'stop': 5222
[['4', '5', '6', '9'], ['6', '6', '6', '6', '5', '5'], ['5', '2', '2', '2']]
Enter an integer, the value ends if it is 'stop': 0
[['4', '5', '6', '9'], ['6', '6', '6', '6', '5', '5'], ['5', '2', '2', '2'], ['0']]

This is the type of output i'm looking for but whenever I press 0...it does not break the loop..

also using if val == list(0) and if list(val) == list(0) and many other permutations either gives me an error or does not break out from the While Loop...Please Help..Thank you

In your example output you do not input 'stop' anywhere. Is this a mistake? It seems from the input message that 'stop' should end the current sub-list and start the next. Please clarify what inputting 'stop' and 0 should do. — Sebastian Baltser
– Sebastian Baltser, Commented Apr 4, 2021 at 17:35
Actually I got the solution...wasn't able to delete it...my mistake was if val == (['0']) — K_menon
– K_menon, Commented Apr 4, 2021 at 17:35
well i intended to use 'stop' or '0'...regardless it had to be a str value inside a list — K_menon
– K_menon, Commented Apr 4, 2021 at 17:37

Sebastian Baltser · Accepted Answer · 2021-04-04 17:28:28Z

1

The returned value of input is an instance of str. So in any case you would need to use the condition val == '0' in your if-statement. But since you are creating a list from the returned value of input you would need to change your code to the following:

values = []
while True:
    val = list(input("Enter an integer, the value ends if it is 'stop': "))
    if val == ['0']:
        exit()
    values.append(val)
    print(values)

answered Apr 4, 2021 at 17:28

Sebastian Baltser

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