How to break loop with ENTER input

Question

I want to break this loop when I press ENTER then display the list but it doesn't recognize '' since it has to be a string

list = []
while True:
    try:
        num = int(input('Enter integers:'))
        list.append(num)
    except ValueError:
        print('Not an integer, try again')
        continue
    if num == '':
        list.sort()
        print(list)
        break

I also want to display "x is not an integer, try again." but I keep getting an error when I try

print(num + 'is not and integer, try again.')

Beside the point, but list is a bad variable name since it shadows the builtin list type. In example code it's not a big problem, just confusing, but it'd be better to use a more descriptive name like numbers. Cf. Why does "example = list(...)" result in "TypeError: 'list' object is not callable"?. — wjandrea
– wjandrea, Commented Jun 22, 2024 at 15:52

Pedro Maia · Accepted Answer · 2021-11-30 13:53:51Z

5

You're converting it to int too early, perform the check and then convert it:

list = []
while True:
    num = input('Enter integers:')
    if num == '':
        list.sort()
        print(list)
        break
    try:
        list.append(int(num))
    except ValueError:
        print('Not an integer, try again')

edited Nov 30, 2021 at 13:53

answered Nov 30, 2021 at 13:49

Pedro Maia

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1 Comment

timgeb Over a year ago

Consider using another name for list.

timgeb · Accepted Answer · 2021-11-30 13:53:50Z

2

If you press enter, num will be the empty string ''.

int('') raises a ValueError which makes the loop continue and skip your breaking condidtion.

edit: rearrange your code like in Pedro's answer.

edited Nov 30, 2021 at 13:53

answered Nov 30, 2021 at 13:48

timgeb

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2 Comments

Pedro Maia Over a year ago

But this would also print 'Not an integer, try again'

timgeb Over a year ago

@PedroMaia true

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